19. Problem 8.85 Consider the collection of nonmetallic elements O,P, Te, I and

Question

19.

Problem 8.85

Consider the collection of nonmetallic elements O,P, Te, I and B.

Part A

Which two would form the most polar single bond?

Part B

Which two would form the longest single bond?

Part C

Which two would be likely to form a compound of formula XY2?

Part D

Which combinations of elements would likely yield a compound of empirical formula X2Y3?

Problem 8.85

Consider the collection of nonmetallic elements O,P, Te, I and B.

Part A

Which two would form the most polar single bond?

Which two would form the most polar single bond? BO TeI IO PO

Part B

Which two would form the longest single bond?

Which two would form the longest single bond? PO TeI BO PI

Part C

Which two would be likely to form a compound of formula XY2?

Which two would be likely to form a compound of formula ? PI2 BO2 PO2 TeI2

Part D

Which combinations of elements would likely yield a compound of empirical formula X2Y3?

Which combinations of elements would likely yield a compound of empirical formula ? B2O3 and P2O3 B2I3 and P2I3 B2O3 and P2I3 B2I3 and P2O3

Explanation / Answer

part A )   answer : B-O

reason : electronegativity difference more so more polar bond

part B ) answer : Te-I

reason : Te 6th group and I 7th group . so there is only little bit difference in electronegativeity so bond in not ggod bond between these two. so bond length more

part C) answer : TeI2

reason : O , S , Se , Te, Po are 6th elements these can form dihalides with formula MX2

example : SCl2, TeCl2 and so on

part D ) B2O3 and P2O3

reason : both Borbon and P having same valancy 3 . so they can form M2O3 type oxides

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