Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Ethene (C2H4) can be halogenated by the following reaction: C2H4(g)+X2(g)C2H4X2(

ID: 927979 • Letter: E

Question

Ethene (C2H4) can be halogenated by the following reaction: C2H4(g)+X2(g)C2H4X2(g) where X2 can be Cl2, Br2, or I2.

1. Use the thermodynamic data given to calculate H for the halogenation reaction by I2 at 17 C.

2. Use the thermodynamic data given to calculate S for the halogenation reaction by I2 at 17 C.

3. Use the thermodynamic data given to calculate G for the halogenation reaction by I2 at 17 C.

4. Use the thermodynamic data given to calculate Kp for the halogenation reaction by I2 at 17 C.

Explanation / Answer

When collecting data, pay attention to the physical state : (g)

                   dH, kJ/mol dS, J/mol.K

C2H4Cl2(g)   dH= -129.7   dS = 308.0
C2H4Br2(g)   dH= -38.3    dS= 330.6
C2H4I2(g)      dH= 66.5      dS= 347.8

Cl2 (g)                  0                 223

Br2 (g)                 31               245

I2 (g)                     62                261

C2H4(g)               52               219

C2H4(g)+X2(g)C2H4X2(g)

1.

dH may be considered as not depending on temperature.

dH = dHC2H4X2 – dHC2H4 – dHX2 = dHC2H4X2 - 52 – dHX2

E.g. for C2H4Cl2(g)     dH = -129.7 -52 -0 = - 181.7 kJ/mol

But for C2H4Br2(g)     dH = -38.3 -52 - 31= - 121.3 kJ/mol

for C2H4I2(g   dH = 66.5 – 52 – 62 = - 47.5 kJ/mol

2.

dS is not temperature dependent

dS = dSC2H4X2 – dSC2H4 – dSX2

E.g. for C2H4I2(g)     dS = 347.8 – 219 - 261 = -132.2 J/mol.K

3.

dG is temperature dependent  

dG=dHo-TdSo

Pay attention to measurement units dH, kJ/mol but dS, J/mol.K

E.g. for C2H4I2(g)   dG = - 47.5 kJ/mol – 290K x (-0. 1322 kJ.mol.K) = - 9.2 kJ/mol

4.

Pay attention to measurement units

lnKp = - dG/RT , it depends on temperature

         = 9200 J/(8.314 J/mol.K x 290 K)=

         = 3.816

Kp = e3.816 = 45.4

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote