46 Calculate the mass percent composition of oxygen in Li,PO 47. Choose the corr

Question

46 Calculate the mass percent composition of oxygen in Li,PO 47. Choose the correct halanced squation that shows the reaction of gaseous ethane with C.26.76 % A.30.72 % D. 55.27% B.17.98 % E. 20.82 % gaseous oxygen to form carbon monoxide gas and water vapor 48. What is the chemical formula for iron (III) sulfide? A. Fe,S B. Fe,so, C. Fe,s, D. Fe (SO) E) Fe,SO 49. What is the molar mass of nitrogen gas? A. 14.0 g/mol B. 6.02 x 10 g/mol C. 7 g/mol D. 1.20 x 10 g/mol E. 28.0 g/mol What is the mass of 1.477 x 10" molecules of NH,? A. 0.00829 g B. 0.417 g C. 2.40 g D. 121 g 50. E. 0.141 g 51. What is the stoichiometrie coefficient for water (H0) when the following equation is balanced using the lowest, whole-number coefficients? coefficients? e the following A. 1 B. 2 C. 3 D. 4 E. 5 52. What is the chemical formula for magnesium hydroxide? A. MgH2 B. MnOH C. MgOH, D. Mg(OH2 E. Mn,OH,

Explanation / Answer

Solution :-

Q46)

molar mass of Li3PO4 = 115.79 g per mol

% of the oxygen = (mass of O/ mass of Li3PO4)*100%

                            = [(4*16)/ 115.79]*100%

                            = 55.27 %

So the correct answer is option D

Q47 )

Balanced reaction is as follows

2 C2H6 (g) + 5 O2 (g)= 4 CO(g) + 6 H2O(g)

So the correct answer is option E

Q48) Iron (lll) sufide means Fe having +3 oxidation state and sulfide ion is S^2-

So the formula is Fe2S3

So the correct answer is option C

Q49)

Molar mass of nitrogen gas (N2) = N*2 = 14.00*2 = 28.0 g per mol

So the correct answer is option E

Q50)

1.477*10^22 molecules of NH3

Mass = ?

(1.477*10^22 molecules * 1 mol / 6.02*10^23 molecules)*(17.03 g / 1 mol ) = 0.417 g NH3

So the correct answer is option B

Q51

Balanced reaction equation is

CH4 + 2O2 ------ > CO2 + o 2 H2O

So the coefficient for the H2O (water) is 2

Therefore correct answer is option B

Q52)

Magnesium hydroxide = Mg(OH)2

So the correct answer is option D

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