The standard cell potential (E degree) of a voltaic cell constructed using the c

Question

The standard cell potential (E degree) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn (s) + 2H^+ (aq) rightarrow Zn^2+ (aq) + H2 (g) With PH2 = 1.0 atm and [Zn^2+] = 1.0 M, the cell potential is 0.66 V. The concentration of H^+ the cathode compartment is M. A voltaic cell is constructed with two Zn^2+ -Zn electrodes, where the half-reaction is Zn^2+ + 2e^- rightarrow Zn (s) E degree = -0.763 V The concentrations of zinc ion in the two compartments are 5.50 M and 1.11 x 10^-2M, respectively. The cell emf is V.

Explanation / Answer

7)As per Nernst equation for the following cell :-

Ecell = E0cell - (0.059/2)*log{[Zn2+]*[PH2]/[H+]2}

or, 0.66 = 0.76 - (0.059/2)*log{1*1/[H+]2}

or, [H+] = 0.02 M

Thus, pH = -log[H+] = 1.695

8) the Nernst Equation for concentraion cells are :-

Ecell = -log[cathode]/[anode] = log{0.011/5.5} = 2.695 V

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