A solution containing bacteria at a concentration of 0.001 g/L was fed to a semi

Question

A solution containing bacteria at a concentration of 0.001 g/L was fed to a semibatch reactor. The nutrient was in excess and the growth rate law is first order in the cell concentration. The reactor was empty at the start of the experiment. If the concentration of bacteria in the reactor at the end of 2 h is 0.025 g/L, what is the specific growth rate k in min-1 ?A solution containing bacteria at a concentration of 0.001 g/L was fed to a semibatch reactor. The nutrient was in excess and the growth rate law is first order in the cell concentration. The reactor was empty at the start of the experiment. If the concentration of bacteria in the reactor at the end of 2 h is 0.025 g/L, what is the specific growth rate k in min-1 ?

Explanation / Answer

1) we know that growth rate = K = rate constant

We know that

ln A =kt + ln A0

Given [A0] = 0.001

[A] = 0.025

t = 2h = 2 X 60 minutes = 120 minutes

-3.68 = k X 120 -6.91

3.229 = k X 120

k = 0.0269 MIN-1

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