calculate the final molarity of K+ (aq) in a solution made by mixing 200 ml of a

Question

calculate the final molarity of K+ (aq) in a solution made by mixing 200 ml of a 0.115M solution of K3PO4(aq) with 300 mL of a 0.225M solution of K2CO3(aq). Note that both salts are completely soluble in water and assume that the volumes are additive calculate the final molarity of K+ (aq) in a solution made by mixing 200 ml of a 0.115M solution of K3PO4(aq) with 300 mL of a 0.225M solution of K2CO3(aq). Note that both salts are completely soluble in water and assume that the volumes are additive calculate the final molarity of K+ (aq) in a solution made by mixing 200 ml of a 0.115M solution of K3PO4(aq) with 300 mL of a 0.225M solution of K2CO3(aq). Note that both salts are completely soluble in water and assume that the volumes are additive

Explanation / Answer

K3PO4 moles = M x V = 0.115 x 200/1000 = 0.023

K+ moles = 3 x K3PO4 moles = 3 x 0.023 = 0.069

K2CO3 moles = 0.225 x 300/1000 = 0.0675

K+ moles = 2 x K2CO3 moles = 2 x 0.0675 = 0.135

total K+ moles = 0.069+0.135 =0.204

total vol = 200+300 = 500 ml = 0.5L

[K+] = ( 0.204/0.5) = 0.408 M

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