1) Give the chemical names for the following a-e in picture. 2) Give the correct
ID: 926917 • Letter: 1
Question
1) Give the chemical names for the following a-e in picture. 2) Give the correct 3-D structures for the given chemical name 3) Draw all the geometric and optical isomers for K_4[Co(Br)_2(C_2O_4)_2] Name all the isomers,assigning absolute configurations to the chiral isomers.1. Give chemical names for the following: c) [CrCl2(NH3)4]CI a) K2FeO4 b) [Cr(NHa)6]Cl3 d) Na[PtCls(CO)] e) Ks[AI(C204)s] 2. Give the correct 3-D structures for the given chemical names: Potassium ethylenediaminetetraacetatocobaltate(I) Sodium cis-dichlorotetracyanochromate (III) fac-triaquatrinitrocobalt(III) Tetraamminecobalt(III)--hydrido--hydroxo-bis(ethylenediamine)cobalt(III) chloride Draw all of the geometric and optical isomers for K[Co(Br)2(C204)2]. Name all the isomers, assigning absolute configurations to the chiral isomers.
Explanation / Answer
1) K2FeO4
K = potassium with +1 oxidation state and Fe has oxidation state ,,let be x O has oxidation state = -2
sum of oxidation states = 0
2(+1) + x +4(-2) = 0
+2+x-8 = 0
x-6 = 0
x= +6
(FeO4) is ferrate ion with oxidation state of Fe = +6
so chemical name is potassium ferrate (VI)
2) [Cr(NH3)6] Cl3
In this cation is Chromium ..let its oxidation state is x
The anions are Cl chloride with oxidation state -1 .
Cr has ligand NH3 with oxidation state = zero ..it is ammine
sum of oxidation states = 0
x+ 6(0) + 3(-1) = 0
x-3= 0
x=+3
so Cr has oxidation state =+3
we , write in alphabetical order (ignoring the prefixes).
hexaamminechromium(III) chloride
3) [Cr Cl2 (NH3)4 ]Cl
we need to find oxidation state of Cr
x+ 2(-1) +4(0) + (-1) = 0
x-2-1= 0
x= +3
oxidation state of Cr = +3
naming alphabetically
(NH3)4 = tetraammine
Cl2= dichloro
Cr= chromium(III)
Cl anion outside brackett = chloride
Name is
tetraamminedichlorochromium(III) chloride.
4) .Na[PtCl3(CO)]
In this the cation (Na) will be named first and separated by a space from the anion
Na= sodium with O.N = +1
Pt = platinum with O.N= x
Cl is chloro with O.N= -1
CO is carbonyl with O.N= zero
sum , +1 + x +3(-1) +0 = 0
+1+x-3 = 0
x-2=0
x=+2
name : Sodium carbonyltrichloroplatinate(II)
5) K3[Al(C2O4)3]
K= potassium with O.N= +1
Al = aluminium with O.N= x
C2O4 is oxalate with O.N= -2
3(+1) +x+ 3(-2)=0
+3+x-6 = 0
x=+3 = Al
Name : Potassium trioxalatoaluminate (III)
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