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1) Give the chemical names for the following a-e in picture. 2) Give the correct

ID: 926917 • Letter: 1

Question

1) Give the chemical names for the following a-e in picture. 2) Give the correct 3-D structures for the given chemical name 3) Draw all the geometric and optical isomers for K_4[Co(Br)_2(C_2O_4)_2] Name all the isomers,assigning absolute configurations to the chiral isomers.
1. Give chemical names for the following: c) [CrCl2(NH3)4]CI a) K2FeO4 b) [Cr(NHa)6]Cl3 d) Na[PtCls(CO)] e) Ks[AI(C204)s] 2. Give the correct 3-D structures for the given chemical names: Potassium ethylenediaminetetraacetatocobaltate(I) Sodium cis-dichlorotetracyanochromate (III) fac-triaquatrinitrocobalt(III) Tetraamminecobalt(III)--hydrido--hydroxo-bis(ethylenediamine)cobalt(III) chloride Draw all of the geometric and optical isomers for K[Co(Br)2(C204)2]. Name all the isomers, assigning absolute configurations to the chiral isomers.

Explanation / Answer

1) K2FeO4   

K = potassium with +1 oxidation state and Fe has oxidation state ,,let be x O has oxidation state = -2

sum of oxidation states = 0

2(+1) + x +4(-2) = 0

+2+x-8 = 0

x-6 = 0

x= +6

(FeO4) is ferrate ion with oxidation state of Fe = +6

so chemical name is potassium ferrate (VI)

2) [Cr(NH3)6] Cl3

In this cation is Chromium ..let its oxidation state is x

The anions are Cl chloride with oxidation state -1 .

Cr has ligand NH3 with oxidation state = zero ..it is ammine

sum of oxidation states = 0

x+ 6(0) + 3(-1) = 0

x-3= 0

x=+3

so Cr has oxidation state =+3

we , write in alphabetical order (ignoring the prefixes).

hexaamminechromium(III) chloride

3) [Cr Cl2 (NH3)4 ]Cl

we need to find oxidation state of Cr

x+ 2(-1) +4(0) + (-1) = 0

x-2-1= 0

x= +3

oxidation state of Cr = +3

naming alphabetically

(NH3)4 = tetraammine

Cl2= dichloro

Cr= chromium(III)

Cl anion outside brackett = chloride

Name is

tetraamminedichlorochromium(III) chloride.

4) .Na[PtCl3(CO)]

In this the cation (Na) will be named first and separated by a space from the anion

Na= sodium with O.N = +1

Pt = platinum with O.N= x

Cl is chloro with O.N= -1

CO is carbonyl with O.N= zero

sum , +1 + x +3(-1) +0 = 0

+1+x-3 = 0

x-2=0

x=+2

name : Sodium carbonyltrichloroplatinate(II)

5) K3[Al(C2O4)3]

K= potassium with O.N= +1

Al = aluminium with O.N= x

C2O4 is oxalate with O.N= -2

3(+1) +x+ 3(-2)=0

+3+x-6 = 0

x=+3 = Al

Name : Potassium trioxalatoaluminate (III)