A. Calculate the concentration in % (w/v) of the standard sugar solutions below.

Question

A. Calculate the concentration in % (w/v) of the standard sugar solutions below. The values of specific gravity are:

Standard Sugar Solution # 1= 1.0145

Standard Sugar Solution # 2= 1.0275

Standard Sugar Solution # 3= 1.0395

Show your calculations below.

B. Plot data points of the 3 standard sugar solutions on a graph. Include the data point for distilled water. Then draw the calibration graph. Label the x-axis & the y-axis.

Y acess:

1.05

1.04

1.03

1.02

1.01

1.00

0.99

X acess: 0 , 2, 4, 6, 8, 10, 12

C. Determine the sugar concentration for Coke & Gatorade by using your calibration graph. Indicate on the calibration graph how you determine the concentrations of each solution.

Information recorded in the lab experiment:

Part C: Specific gravity of sugar solutions:

Standard Sugar Solutions/ Mass of Sugar/ Voume of Solution/ Specific Gravity

#1 / 18.03g / 500.0mL / 1.0145

#2 / 36.01g / 500.0mL / 1.0275

#3 / 53.03g / 500.0mL / 1.0395

Part B: Specific gravity of soft/sports drinks:

Solution / Specific Gravity

Coke / 1.0495

Gatorade / 1.0245

Part C:

standard sugar solution / mass of sugar / volume of solution / specific gravity

#1 / 18.03 g/ 500.00mL / 1.0145

#2 / 36.01g / 500.00mL / 1.0275

#3 / 53.03g / 500.00mL / 1.0395

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Explanation / Answer

A. Specific gravity of standard Sugar Solution # 1= 1.0145

Density of Sugar Solution # 1 / Density of water = 1.0145

We know that density of water = 1.0 g/mL

Density of Sugar Solution # 1 = 1.0145 g/mL

Mass present in 100 mL = 1.0145 * 100 = 101.45 gm

So, concentration in % (w/v) = 101.45 (gm / 100 mL) %

Specific gravity of standard Sugar Solution # 2 = 1.0275

Density of Sugar Solution # 2 / Density of water = 1.0275

Density of Sugar Solution # 2 = 1.0275 g/mL

Mass present in 100 mL = 1.0275 * 100 = 101.45 gm

So, concentration in % (w/v) = 102.75 (gm / 100 mL) %

Specific gravity of standard Sugar Solution # 3 = 1.0395

Density of Sugar Solution # 3 / Density of water = 1.0395

Density of Sugar Solution # 3 = 1.0395 g/mL

Mass present in 100 mL = 1.0395 * 100 = 103.95 gm

So, concentration in % (w/v) = 103.95 (gm / 100 mL) %

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