Titration of Vinegar HC_2H_3 O_2(aq)+Nac_2 H_ 3 (aq)+H_2O(aq) In a titration, 12

Question

Titration of Vinegar HC_2H_3 O_2(aq)+Nac_2 H_ 3 (aq)+H_2O(aq) In a titration, 12.00 mL of a solution of vinegar containing acetic acid, HC_2H_3O_2, is titrated to its end point with 25.00 mL of 0.4000 M NaOH, according to the reaction she"'i above. What is the concentration (in M)' of acetic acid in the vinegar solution. The molar concentration of an acetic acid solution is measured to be 0.7548 mol/L. What is the percentage of acetic acid by mass in this solution Assume that the density of this solution is 1.000 g/ml.

Explanation / Answer

a. The problem can be solved by using the following equation

M1V1 = M2V2

M = molarity. and V = volume

1 correspond to vinegar and 2 correspond to NaOH

12 X M1 = 25 X 0.4

M1 = 0.83M

b.

mass of acetic acid present in one liter solution (M) = molarity X molecular mass

M = 0.7548 X 60

M = 45.288

mass of 1 liter solution = volume X density = 1000mL X 1 = 1000g

pecntage of acetic acid = (45.288 / 1000) X 100

pecntage of acetic acid = 4.5288

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