At 298 K, for the reaction 2H+(aq)+2Br(aq)+2NO2(g)Br2(l)+2HNO2(aq)H= - 61.6 kJ a

Question

At 298 K, for the reaction 2H+(aq)+2Br(aq)+2NO2(g)Br2(l)+2HNO2(aq)H= - 61.6 kJ and the standard molar entropies are H+(aq), 0 JK1; Br(aq), 82,4JK1; NO2(g), 240.1 JK1; Br2(l), 152.2 JK1; HNO2(aq), 135.6 JK1.

Part A

Determine G at 298 K.

Express your answer to two significant figures and include the appropriate units.

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Part B

Determine whether the reaction proceeds spontaneously in the forward or the reverse direction when reactants and products are in their standard states.

At 298 K, for the reaction 2H+(aq)+2Br(aq)+2NO2(g)Br2(l)+2HNO2(aq)H= - 61.6 kJ and the standard molar entropies are H+(aq), 0 JK1; Br(aq), 82,4JK1; NO2(g), 240.1 JK1; Br2(l), 152.2 JK1; HNO2(aq), 135.6 JK1.

Part A

Determine G at 298 K.

Express your answer to two significant figures and include the appropriate units.

G=

SubmitMy AnswersGive Up

Part B

Determine whether the reaction proceeds spontaneously in the forward or the reverse direction when reactants and products are in their standard states.

Determine whether the reaction proceeds spontaneously in the forward or the reverse direction when reactants and products are in their standard states. reverse direction forward direction equilibrium

Explanation / Answer

2H+ + 2Br- + 2NO2 --> Br2+ 2HNO2 HRXN = -61.6

S = Sprod - Sreact = 152.2 + 2*135.6 - (2*0 + 2*82.4 + 2*240) = -221.4 J/molK

Srxn = -221.4 J/molK

Hrxn = -61600 J/mol

Then

G = H-TS = -61600 - (298)(-221.4) = 4377.2 J/mol or 4.37 kJ/mol

2)

Since G >0, this is NOT spontaneous, this is favoured towards reactants

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