At 22°C, Kp= 0.070 for the equilibrium: NH4HS (s) ---> NH3 (g) + H2S (g) A sampl

Question

At 22°C, Kp= 0.070 for the equilibrium:
NH4HS (s) ---> NH3 (g) + H2S (g)

A sample of solid NH4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (atm) of ammonia, assuming that some solid NH4HS remains.

a) 0.26
b) 0.070
c) 0.52
d) 4.9x10^(-3)
e) 3.8

I tried this but I didn't know what more I can do.

At 22degreeC, Kp= 0.070 for the equilibrium: NH4HS (s) right arrow NH3 (g) + H2S (g) A sample of solid NH4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (atm) of ammonia, assuming that some solid NH4HS remains. a) 0.26 b) 0.070 c) 0.52 d) 4.9x10^(-3) e) 3.8 I tried this but I didn't know what more I can do.

Explanation / Answer

Kp = P(NH3)P(H2S)/1, let x be the amount of NH4HS dissociated.

0.07 = x2 => x = 0.26

Partial pressure of NH3 is 0.26 atm. Answer (a)

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