consider the following electrolysis reactions. Assume T = 298 K. Here is a table

Question

consider the following electrolysis reactions. Assume T = 298 K. Here is a table of standard reduction potentials. If current is negligible, What voltage must be applied to drive the net reaction? If the cell has a resistance of 2.3 ohm and a current of 270 mA, Calculate the ohmic potential of the cell Calculate the potential that needs to be applied in order drive the reaction considering the ohmic potential calculated in part b and an anodic overpotential of 0.25 V and a cathodic overpotential of 0.54 V. If concentration polarization occurs in the cell and [Al3+]s becomes 0.007 M, while [AU3+]S BECOMES 0.97 M, What potential must be applied to drive the reaction? Assume the resistance, current, and overpotentials all remain the same as in parts b and c. Consider the following electrolysis reactions. Assume T = 298 K. Here is a table of standard reduction potentials. If current is negligible, What voltage must be applied to drive the net reaction? If the cell has a resistance of 2.3 ohm and a current of 270 mA, Calculate the ohmic potential of the cell Calculate the potential that needs to be applied in order drive the reaction considering the ohmic potential calculated in part b and an anodic overpotential of 0.25 V and a cathodic overpotential of 0.54 V. If concentration polarization occurs in the cell and [Al3+]s becomes 0.007 M, while [AU3+]S BECOMES 0.97 M, What potential must be applied to drive the reaction? Assume the resistance, current, and overpotentials all remain the same as in parts b and c.Chart by using the Nernst equation to determine the potential of each half cell, then use that information to figure out how much voltage would be needed to drive the reaction. For part b, think of an equation to calculate the ohmic potential. In part c,how are ohmic potential and overpotentials related to the potential needed to drive a reaction? For part d, consider how the analytic concentration at the surface of the electrode would affect the potential at each electrode. where E is the cell potential, Eo is the standard potential, n is the number of electrons involved in the reaction, and Q is the reaction quotient for the reaction.

Explanation / Answer

1)ohmic potential = current * resistance

=2.3*0.27

=0.621 V

b)anodic overpotential = 0.25

so, total potential = 0.621-0.25+0.54

=0.911 V

c)E=0.911 + (0.059/3)*log(0.007/0.97)

=0.86888

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