Based on the electron configuration and number of unpaired electrons, which are

Question

Based on the electron configuration and number of unpaired electrons, which are diamagnetic?

Electron configuration of Cu2+ is [Ar]3d(8)4s(2) and no. of unpaired electron is 2

Electron configuration of Mo4+ is [Kr]4d25s0 and no. of unpaired electron is 2

Electron configuration of Ce is [Xe] 4f1 5d1 6s2 and no. of unpaired electron is 2

Electron configuration of Sn is [Kr] 4d10 5s2 5p2 and no. of unpaired electron is 2

Electron configuration of V5+ is 1s2 2s2 2p6 3s2 3p6 and no. of unpaired electron is 0

Electron configuration of Sc2+ is 1s22s22p63s23p64s1 and no. of unpaired electron is 1

Explanation / Answer

If there are unpaired electrons in the atom or ion then it is paramagnetic & if there are no unpaired electrons it is diamagnetic.

Electron configuration of Cu2+ is [Ar]3d(8)4s(2) and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of Mo4+ is [Kr]4d25s0 and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of Ce is [Xe] 4f1 5d1 6s2 and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of Sn is [Kr] 4d10 5s2 5p2 and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of V5+ is 1s2 2s2 2p6 3s2 3p6 and no. of unpaired electron is 0 ----- diamagnetic

Electron configuration of Sc2+ is 1s22s22p63s23p64s1 and no. of unpaired electron is 1 ------ para magnetic

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