For the reaction: l^-(aq) + OCl^-(aq) reversible Ol^-(aq) + Cl^-(aq) occurring i

Question

For the reaction: l^-(aq) + OCl^-(aq) reversible Ol^-(aq) + Cl^-(aq) occurring in aqueous solution, the following mechanism has been proposed: OCl^-(aq) + H_2O(l) reversible^k_1 _k_-1 HOCl(aq )+ OH^-(aq) I^-(aq) +HOCl(aq) right arrow HOI(aq) + Cl^_(aq) HOl(aq) + OH^-(aq) right arrow H_2O(l) + Ol^-(aq) Derive the rate law expression for this reaction based on the mechanism. The initial rate of reaction was studied as a function of concentration and the following data were obtained: Is the predicted rate law expression consistent with these data? Explain.

Explanation / Answer

(a)

rate = k [I-]1 [OCl-]1 [OH-]0

(b)

rate= k [I-]x [OCl-]y [OH-]z

from data table

1.8 x 10^-4 =k [2.0 x 10^-3]x [1.5 x 10^-3]y [1.00]z ------------->(1)

3.6 x 10^-4 =k [4.0 x 10^-3]x [1.5 x 10^-3]y [1.00]z ------------->(2)

1.8 x 10^-4 =k [2.0 x 10^-3]x [3.0 x 10^-3]y [2.00]z ------------->(3)

7.2 x 10^-4 =k [4.0x 10^-3]x [3.0 x 10^-3]y [1.00]z ------------->(4)

by solving 1 and 2

x = 1

by solving 2 and 4

y = 1

by solving 3 and 4

z = -1

rate= k [A]1 [B]1 [C]-1

Total order = 1 + 1 + -1 = 1

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.