And the change in temperature is 3.17 C What is the energy released/absorbed by

Question

And the change in temperature is 3.17 C

What is the energy released/absorbed by the solution, the calorimeter, and the reaction? (in joules)

Enthalpy is always reported with respect to a reactant. Calculate the Enthalpy change, ?H, for Reaction 2 in kJ / mole NaOH.  Your answer should have the correct sign to reflect whether this is an endothermic or exothermic process.

1 NH4Cl (aq) + 1 NaOH (aq) 1 NH3 (aq) + 1 H2O (l) + 1 NaCl (aq)

And the change in temperature is 3.17 C

What is the energy released/absorbed by the solution, the calorimeter, and the reaction? (in joules)

Enthalpy is always reported with respect to a reactant. Calculate the Enthalpy change, ?H, for Reaction 2 in kJ / mole NaOH.  Your answer should have the correct sign to reflect whether this is an endothermic or exothermic process.

Reaction 2: Sodium hydroxide + Ammonium chloride Volume of 2.0 M NaOH(aa) used 24.98 mL Lnitial temperature of the 2.0 M NaOH(a) 19.87 oC Volume of 2.0 M NH4Cla) used 25.0 mL Maximum temperature of the 2.0 M NH4Cl(ag) 23.04

Explanation / Answer

NH4Cl (aq) + NaOH (aq) ---->   NH3 (aq) + H2O (l) + NaCl (aq)

no of mol of NaOH = 24.98/1000*2 = 0.05 mol

No of mol of NH4Cl = 25/1000*2 = 0.05 mol

q released = m*s*DT

let us assume density of solution = 1 g/cc

mass of solution = (24.98+25) = 49.98 grams

specific heat of solution = 4.18 j/g.c

            = 49.98*4.18*(23.04-19.87)

            = 662.265 joule.

            = 0.662 kj

DH = -q/n = -0.662/0.05 = -13.24 kj/mol

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