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Determine Zip-Lock Bag Volume (Check off 100 mL additions as H:0 is added) 100 m

ID: 919513 • Letter: D

Question

Determine Zip-Lock Bag Volume (Check off 100 mL additions as H:0 is added) 100 mL 200 mL 300 mL 400 mL. 500 mL 600 mL 700 mL 800 mL 900 mL 1000 mL 1100 mL 1200 mL AdditionalmLs TOTAL H,O ADDED:790ml . Calculate Amount of Sodium Bicarbonate Required Volume Temperature Pressure NaHCO, 85 mL 0-78 L 1 °CILA4.IS 69 mm Hg 0.40 Atm O3 moles 2.52 grams R = 0.0821 L-atm / moles-K ar mass of NaHCo,? ·de g2m/ 1. What is the molar mass of NaHCO,? Calculation (0-909)(0.78)nlo.oe9u.s) 109 emistry 131 EXPERIMENT 11

Explanation / Answer

I really don't understand what do you actually want. The whole answer for the 3 problems are there. However, I'll do it with the data you are providing:

1. The amount of NaHCO3 required, if you have pressure, volume and T, use the ideal gas equation:

PV = nRT

n = PV / RT = 0.909 * 0.785 / 0.082 * 294.15

n = 0.0296 moles

Now the molar mass, we need the atomic mass of every atom of the NaHCO3

Na = 23 g/mol; H = 1 g/mol; C = 12 g/mol; = = 16 g/mol

MM = 23 + 1 + 12 + 3(16) = 84 g/mol

3. As we are using H2SO4 the reaction is as follow:

2NaHCO3 + H2SO4 --------> Na2SO4 + 2H2O + 2CO2

n = PV /RT = 0.909 * 0.785 / 0.0821 * 294.15

n = 0.0295 moles

But 2 moles of bicarbonate reacts with 1 mol of H2SO4, so:

n = 0.0295 * 2 = 0.059 moles.

m = 0.059 * 84 = 4.96 g

2. 0.0295 * 84 = 2.478 g

Hope this helps.

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