Given the values of H rxn, S rxn, and T below, determine S univ. Part A H rxn= 8

Question

Given the values of Hrxn, Srxn, and T below, determine Suniv.

Part A

Hrxn= 84 kJ , Srxn= 142 J/K , T= 310 K

Express your answer using two significant figures.

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Part B

Hrxn= 84 kJ , Srxn= 142 J/K , T= 764 K

Express your answer using one significant figure.

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Part C

Hrxn= 84 kJ , Srxn= 142 J/K , T= 310 K

Express your answer using two significant figures.

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Part D

Hrxn= 84 kJ , Srxn= 142 J/K , T= 405 K

Express your answer using two significant figures.

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Part E

Predict whether or not the reaction in part A will be spontaneous.

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Part F

Predict whether or not the reaction in part B will be spontaneous.

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Part G

Predict whether or not the reaction in part C will be spontaneous.

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Part H

Predict whether or not the reaction in part D will be spontaneous.

Given the values of Hrxn, Srxn, and T below, determine Suniv.

Part A

Hrxn= 84 kJ , Srxn= 142 J/K , T= 310 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part B

Hrxn= 84 kJ , Srxn= 142 J/K , T= 764 K

Express your answer using one significant figure.

Suniv =   J/K  

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Part C

Hrxn= 84 kJ , Srxn= 142 J/K , T= 310 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part D

Hrxn= 84 kJ , Srxn= 142 J/K , T= 405 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part E

Predict whether or not the reaction in part A will be spontaneous.

Predict whether or not the reaction in part A will be spontaneous. spontaneous nonspontaneous

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Part F

Predict whether or not the reaction in part B will be spontaneous.

Predict whether or not the reaction in part B will be spontaneous. spontaneous nonspontaneous

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Part G

Predict whether or not the reaction in part C will be spontaneous.

Predict whether or not the reaction in part C will be spontaneous. spontaneous nonspontaneous

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Part H

Predict whether or not the reaction in part D will be spontaneous.

Predict whether or not the reaction in part D will be spontaneous. spontaneous nonspontaneous

Explanation / Answer

A. dSrxn

=142 J/K

= 0.142kJ/K

H°rxn = 84 kJ
For surroundings, dQ = -dH

Ssurroundings = -dH/ T = -84kJ/310K = -0.27 kJ/K

Suniverse= S sys + S surroundings = - 128.97 J/K

B. Ssurroundings = -dH/ T = -84kJ/764K = -0.11 kJ/K

Suniverse= S sys + S surroundings = - 0.13 kJ/K = 32.05 J/K

C. Ssurroundings = -dH/ T = -84kJ/310K = -0.27 kJ/K

Suniverse= S sys + S surroundings = - 412.97 J/K

D. Ssurroundings = -dH/ T = 84kJ/405K = 0.21 kJ/K

Suniverse= S sys + S surroundings = 349.40 J/K

E. dGreaction = dHreaction - TdSreaction = 84000 - 310*142= 40 kJ ....[nonspontaneous]

F. dGreaction = dHreaction - TdSreaction = 84000 - 764*142 = -24.5 kJ ....[spontaneous]

G. dGreaction = dHreaction - TdSreaction = 84000 - 310(-142) = 128 kJ....[ nonspontaneous]

H. dGreaction = dHreaction - TdSreaction = - 84000 - 405*142 = -141.5 kJ ....[spontaneous]

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