1. Calculate the solubility of MgF2, in water at 25C units of a) Moles per liter

Question

1. Calculate the solubility of MgF2, in water at 25C units of a) Moles per liter and b) Grams per liter. Ksp is 7.4 x 10^-11. RECALCULATE when mixed with 0.1 M NaF

2.A particular saturated solution of silver chromate has (Ag2CrO4) has [Ag+] = 5.0 x 10^-5 and [CrO4^2-]= 4.4 x 10^-4 M. What is the value of Ksp for Ag2CrO4?

3.Calculate the molar solubility ofAgCI at 25c a) pure water and b) 2.0 M NH3

4. Calculate the solubility in g/L of AgBr in a) pure water and 0.01M NaBr

5. If 2.5 g of copper sulfate is dissolved in 900 mL of 0.3M NH3 what are the concentrations of Cu^2+, Cu(NH3)4^2+ and NH3 at equilibrium.

Explanation / Answer

1.

MaF2 solubility product Ksp = 5.16 x 10^-11

MgF2 <------------------------> Mg+2 + 2F-

                                             S            2S

Ksp = [Mg+2][F-]^2 = (S) (2S)^2

Ksp =4S^3

5.16 x 10^-11 = 4 S^3

S = 2.34 x10^-4 M

solubilty = 2.34 x10^-4   mol / Litre

MgF2 molar mass = 62.3 g /mol

solubility in g/L = 2.34 x10^-4   mol / Litre   x 62.3 g /mol = 0.0146 g/L

when 0.1 NaF added

[F-]   = 0.1 M

Ksp = S   x (0.1)^2

5.16 x 10^-11 = S   x (0.1)^2

S = 5.16 x 10^-9 M

solubility = 5.16 x 10^-9 mol / L

solubility in g/L = 3.21 x 10^-7 g/L

2.)

Ksp = [Ag+]^2 [CrO4^-2]

Ksp = (5 x 10^-5)^2 (4.4 x 10^-4 )

Ksp = 1.1 x 10^-12

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