1. Calculate the moment of inertia of a CD, including the effect of the hole. Fo

Question

1.Calculate the moment of inertia of a CD, including the effect of the hole. For a CD of radius 3.0 cm, estimate the percentage change in the moment of inertia due to a hole of radius 7 mm. (Neglect the difference in mass due to the hole.)

2.For the system below, m1 = 14 kg, m2 = 23 kg and mpulley = 18 kg, if the coefficient of friction between crate 1 and the table is ?K = 0.17, what is the acceleration?

3.A board of length 2.1 m is attached to a floor with a hinge at one end as shown in the figure below. The board is initially at rest and makes an angle of 39

Explanation / Answer

1) [1/2M(R^2-r^2)/1/2MR^2]x100% =

(R^2-r^2)/R^2x100% = [1-(r/R)^2]x100%

for r=0.7cm and R=3cm, we have

[1-(0.7/3)^2]x100% = 94.55% meaning the actual value of the moment of inertia is 98.6% of what it would be if there were no hole, so the hole contributes a loss of 5.44%

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