Suppose a mutation occurs in the promoter region of a bacterial gene. Researcher

Question

Suppose a mutation occurs in the promoter region of a bacterial gene. Researchers discover that the gene is no longer expressed as a result of this mutation. Which of the following is the mostly likely explanation? a. Translation elongation is inhibited by the mutation. b. Transcription initiation is inhibited by the mutation. c. Transcription elongation is inhibited by the mutation. d. Translation initiation is inhibited by the mutation. A mutation occurs in a gene that results in an mRNA that codes for a premature stop codon. What happens during transcription when the RNA polymerase reaches the nucleotides that code for the stop codon? a. RNA polymerase will not be affected by the mutation and will continue to read through the sequence. b. RNA polymerase will stop when it reaches the first nucleotide coding for the premature codon. c. RNA polymerase will stop when it reaches the last nucleotide coding for the premature codon. d. RNA polymerase will replace th

Explanation / Answer

6.The correct answer is:b.transcription initiation is inhibited by mutation.

Reason:Since RNA polymerase binds to promoter region and initiates transcription, when mutation in promoter occurs, RNA polymerase fails to bind to promoter and transcription initiation is inhibited.

7.The correct answer is:a.RNA polymerase will not be affected by the mutation and will continue to read through the sequence.

Reason:RNA polymerase does not recognise codons neither start or stop.So,it continues to read through the sequence.

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