A 10 wt% aqueous sulfuric acid solution ( = 1.066 g/mL) flows through a 75 m lon

Question

A 10 wt% aqueous sulfuric acid solution ( = 1.066 g/mL) flows through a 75 m long pipe with a 4 cm diameter at a rate of 94 L/min.

a) What is the molarity of sulfuric acid in the solution?

b) How long (in seconds) would it take to fill a 55-gallon drum, and how much sulfuric acid (lbm) would the drum contain? (You should arrive at your answers with two, dimensional equations.)

c)

a) What is the molarity of sulfuric acid in the solution?

b) How long (in seconds) would it take to fill a 55-gallon drum, and how much sulfuric acid (lbm) would the drum contain? (You should arrive at your answers with two, dimensional equations.)

c)

Explanation / Answer

a) Let us consider 1 kg solution = 1000 g

Volume of solution = mass/density = 1000 / 1.066 = 938 ml = 0.938 L

for 1 kg solution sulphuric acid present = ( 10/100) x 1 = 0.1 kg = 100 g

sulphuric acid moles = mass/molar mass = 100 / 98.079 = 1.0196

Molarity = moles of H2SO4 / solution vol in L = 1.0196 /0.938 = 1.087 M

b) 55 galons = 55 x 3.78541 = 208.19755 L

Rate of slow = 94 L /min

we need 208.19755 L

Hence time = Volume / rate = 208.19755 /94 = 2.21486 min

Time in s = 60 x time in min = 2.24186 x 60 =132.9 s = 133 s

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