CHEM 361 Assignment 8 (OUTOF50PTS) Please complete this assignment by 1. What pr

Question

CHEM 361 Assignment 8 (OUTOF50PTS) Please complete this assignment by 1. What pressure is required to compress an ideal gas from 100 ft and 1.00atm to 2.00 ft under isothermal conditions? 2. A rubber balloon was filled with helium at 25 Cand placed in a beaker of liquid nitrogen at -196 C. The volume of the cold helium was 15 cm3 Assuming ideal gas behavior and isobaric conditions, what was the volume of the helium at 25 C? 3. According to Gay-Lussac's law of combining volumes, 2Lof hydrogen gas will react with 1 Lof oxygen gas (measured at the same temperature and pressure) to produce steam. What volume of steam will be formed? 4. A toy balloon originally held 1.00gof helium gas and had a radius of 10.0 cm. During the night, 0.25 g of the gaseffused from the balloon. Assuming ideal gas behavior under these constant pressure and temperature conditions, what was the radius of the balloon the next morning? 5. What is the mass of air in a 250-mL Erlenmeyer flask (actual volume is 267 mL) at a typical laboratory pressure of 715 torr and a temperature of 21 C? Assume air to be an ideal gas having an average molar mass of 29.0 g/mol. 6. How many molecules of gas are in a 0.535-L vacuum system at a pressure of 3.5 x 107 torr and 25 C? Assume ideal gas behavior. 7. A 1.00-mol sample of O2 and a 3.00-mol sample of H2 are mixed isothermally in a 125.3-L container at 125 C. Assuming ideal gas behavior, calculate the partial pressure of each gas and the total pressure of the gaseous mixture. 8. The pressure of a gaseous mixture of NH3 and N2 decreased from 1.50 kPa to 1.00 kPa after the NH3 was absorbed from the mixture. Assuming ideal gas behavior, find the composition of the original mixture. 9. A mixture of ethane and ethene pied 35.5 L at 1.000 bar and 405 K. This mixture reacted completely with 110.3gof O2 to produce CO2 and H20. What was the composition of the original mixture? Assume ideal gas behavior.

Explanation / Answer

1 )  

P1 V1 = P2 V2

1 x 10 = P2 x 2

P2 = 5 atm

2)

T1 = 273 -196 = 77 K

V1 = 15 cm3

T2 = 273 + 25 = 298 K

V2 = ?

T1 / V1 = T2 / V2

77 / 15 = 298 / V2

V2 = 58.05 cm^3

3)

2 H2    + O2 -------------------> 2 H2O

2parts 1part                         2parts

2 L           1 L                            2L

steam volume = 2 L

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