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Hardy-Weinberg Equilibrium Problems p is the frequency of the dominant allele in

ID: 91123 • Letter: H

Question

Hardy-Weinberg Equilibrium Problems

p is the frequency of the dominant allele in the population

q is the frequency of the recessive allele in the population

p2 is the frequency of the homozygous dominant genotype

q2 is the frequency of the homozygous recessive genotype

2pq is the frequency of the heterozygous genotype

p + q = 1

p2 + 2pq + q2 = 1 Find q2 q p p2 2pq

Problem 1

100 Rabbits p ~ B and q ~ b

75 Brown Brown: BB or Bb

25 White White: bb

What is the frequency of the BB, Bb, and bb genotypes in this population of rabbits?

BB + 2(Bb) + bb = 1

Explanation / Answer

Total number of rabbits = 100.

Number of white rabbits = 25.

Frequency of bb =q^2 = 25/100 = 0.25.

q^2 = 0.25, therefore q = 0.5.

Genotype frequency of bb= 0.25

P+ q = 1, P= 1-q = 1- 0.5 = 0.5.

Therefore frequency of dominant allele B = P= 0.5.

Genotype frequency of BB = P^2 = (0.5)^2 = 0.25.

Genotype frequency of Bb = 2Pq = 2 × 0.5 × 0.5 = 0.5.

BB= 0.25.

bb = 0.25.

Bb = 0.5.

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