Hardy-Weinberg Equilibrium Problems p is the frequency of the dominant allele in
ID: 91123 • Letter: H
Question
Hardy-Weinberg Equilibrium Problems
p is the frequency of the dominant allele in the population
q is the frequency of the recessive allele in the population
p2 is the frequency of the homozygous dominant genotype
q2 is the frequency of the homozygous recessive genotype
2pq is the frequency of the heterozygous genotype
p + q = 1
p2 + 2pq + q2 = 1 Find q2 q p p2 2pq
Problem 1
100 Rabbits p ~ B and q ~ b
75 Brown Brown: BB or Bb
25 White White: bb
What is the frequency of the BB, Bb, and bb genotypes in this population of rabbits?
BB + 2(Bb) + bb = 1
Explanation / Answer
Total number of rabbits = 100.
Number of white rabbits = 25.
Frequency of bb =q^2 = 25/100 = 0.25.
q^2 = 0.25, therefore q = 0.5.
Genotype frequency of bb= 0.25
P+ q = 1, P= 1-q = 1- 0.5 = 0.5.
Therefore frequency of dominant allele B = P= 0.5.
Genotype frequency of BB = P^2 = (0.5)^2 = 0.25.
Genotype frequency of Bb = 2Pq = 2 × 0.5 × 0.5 = 0.5.
BB= 0.25.
bb = 0.25.
Bb = 0.5.
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