Hardy-Weinberg Equilibrium In human population X, consider the simple Mendelian

Question

Hardy-Weinberg Equilibrium In human population X, consider the simple Mendelian trait for freckles. F is the dominant allele and f is the recessive allele. Individuals who are homoygous dominant (FF) or heterozygous (Ff) for the trait express freckles. Individuals who are homozygous recessive (ff) for the trait do not express freckles. In this population, 30% (0.3) of the alleles are recessive and 70% (0.7) are dominant (F). Use the Hardy-Weinberg equation to determine the genotype frequencies we should expect in the next generation. Show your work.

Explanation / Answer

here given frequency values are

p for dominant allele (F) = 0.7 and q for recessive allele(f)=0.3

from Hardy- Weinberg equation expected frequency of genotype in next generation will be

Homozygous dominant (FF) frequency= p2 =0.7x0.7=0.49

Heterozygous frequency = 2pq = 2x0.3x0.7 = 0.42

Homozygous recessive frequency= q2 = 0.3x0.3= 0.09

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