calculate the pH of each solution given the following H3O+ or OH- values A. H3O+
ID: 910970 • Letter: C
Question
calculate the pH of each solution given the following H3O+ or OH- valuesA. H3O+ = 1.5x10^-8 M B. H3O+ = 5.5x10^-6 M C. OH- = 8.0 x 10^-2 M D. OH- = 7.0x 10^-3 M E. OH- = 3.0 x 10^-6M F. H3O+ = 5.5 x 10^-2
calculate the pH of each solution given the following H3O+ or OH- values
A. H3O+ = 1.5x10^-8 M B. H3O+ = 5.5x10^-6 M C. OH- = 8.0 x 10^-2 M D. OH- = 7.0x 10^-3 M E. OH- = 3.0 x 10^-6M F. H3O+ = 5.5 x 10^-2
calculate the pH of each solution given the following H3O+ or OH- values
A. H3O+ = 1.5x10^-8 M B. H3O+ = 5.5x10^-6 M C. OH- = 8.0 x 10^-2 M D. OH- = 7.0x 10^-3 M D. OH- = 7.0x 10^-3 M E. OH- = 3.0 x 10^-6M E. OH- = 3.0 x 10^-6M F. H3O+ = 5.5 x 10^-2
Explanation / Answer
A. H3O+ = 1.5x10^-8 M
pH = -log(H3O+) = -log(1.5*10^(-8)) = 7.824
B. H3O+ = 5.5x10^-6 M
pH = -log(H3O+) = -log(5.5*10^(-6)) = 5.26
C. OH- = 8.0 x 10^-2 M
pOH = -log(OH-) = -log(8.0*10^(-2)) = 1.1
pH = 14-1.1 = 12.9
D. OH- = 7.0x 10^-3 M
pOH = -log(OH-) = -log(7*10^(-3)) = 2.155
pH = 14-2.155 = 11.845
E. OH- = 3.0 x 10^-6 M
pOH = -log(OH-) = -log(3*10^(-6)) = 5.23
pH = 14-5.23 = 8.77
F. H3O+ = 5.5 x 10^-2
pH = -log(H3O+) = -log(5.5*10^(-2)) = 1.26
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