1) How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? -
ID: 910476 • Letter: 1
Question
1) How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution?
-is it 43.83 g?
2) Consider the following balanced reaction. How many moles of O2 are formed when 58.6 g of KNO3 decomposes? MM KNO3 is 101.11g/mol.
4 KNO3(s) --> 2 K2O (s) + 2 N2(g) + 5 O2 (g)
3) Consider the following balanced reaction. How many liters of 0.260 M Na2S are needed to react with 0.04000 L of 0.315 M AgNO3?
Na2S (aq) + 2 AgNO3(aq) --> 2 NaNO3(aq) + Ag2S(s)
4) Consider the following balanced reaction. How many moles of Fe(OH)2 can form from 0.1750 L of 0.227 M LiOH solution?
F3Cl2(aq) + 2 LiOH(aq) --> Fe(OH)2(s) + 2 LiCl (aq)
Explanation / Answer
1)
moles of NaCl = 500 x 1.5 / 1000 = 0.75
moles = mass / molar mass
0.75 = mass / 58.5
mass of NaCl = 43.875 g
2)
4 KNO3(s) ------------> 2 K2O (s) + 2 N2(g) + 5 O2 (g)
moles of KNO3 = 58.6g / 101.11
= 0.58
4 mol of KNO3 ---------------- give 5 mol of O2
0.58 mol of KNO3 --------------- ??
moles of O2 = 0.58 x 5 / 4 = 0.725
moles of O2 =0.725
3)
Na2S (aq) + 2 AgNO3(aq) ------------------> 2 NaNO3(aq) + Ag2S(s)
moles of AgNO3 = 0.04 x 0.315 = 0.0126
1 mol of Na2S need ---------------- 2 mol of AgNO3
?? mol of Na2S ------------- 0.0126 mol AgNO3
moles of Na2S = 6.3 x 10^-3
moles = molarity x volume
0.0063 = 0.26 x volume
volume of Na2S = 0.02423 L
4)
FeCl2(aq) + 2 LiOH(aq) --> Fe(OH)2(s) + 2 LiCl (aq)
moles of LiOH = 0.1750 x 0.227 = 0.0397
2 mol LiOH forms ---------------- 1 mol Fe(OH)2
0.0397 mol LiOH --------------- ??
moles of Fe(OH)2 = 0.0397 / 2 = 0.01086
moles of Fe(OH)2 = 0.01086
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