Sulfuryl chloride (S02C12) decomposes to sulfur dioxide (SO2) and chlorine (Cl2)

Question

Sulfuryl chloride (S02C12) decomposes to sulfur dioxide (SO2) and chlorine (Cl2) by reaction in the gas phase. The following pressure data were obtained when a sample containing 5.00 x 10^-2 mol sulfuryl chloride were heated to 600 K a 5.00 x 10^-1 L container Time (hours): 0.00 1.00 2.00 4.00 8.00 16.00 Psoc,2 (atm) 4.93 4.26 3.52 2.53 1.30 0.34 Defining the rate as delta[SO2CI2]/delta T a) Determine the value of the rate constant in the decomposition of sulfuryl chloride at 600K b) What is the half-life of the reaction? c) What fraction of the sulfuryl chloride remains after 20.0 h?

Explanation / Answer

For decomposition of SO2Cl2

a) rate constant k = (ln(4.93) - ln(4.26))/1 = 0.15 h-1

b) half-life = ln(2)/0.15 = 4.62 h

c) after t = 20 h

ln(SO2Cl2) = ln(0.34) - 0.15 x 20

(SO2Cl2) remained = 0.017 atm

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