Buffer solutions can be produced by mixing a weak acid with its conjugate base o

Question

Buffer solutions can be produced by mixing a weak acid with its conjugate base or by mixing a weak base with its conjugate acid. The Henderson-Hasselbalch equation, pH=pKa+log[base][acid] allows you to calculate the pH of a buffer. Note that molarity, moles, and millimoles are all proportional, so you can substitute the number moles, or millimoles, for the concentration terms in this formula.

You need to produce a buffer solution that has a pH of 5.32. You already have a solution that contains 10. mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pKa of acetic acid is 4.74. Express your answer numerically in millimoles.

Explanation / Answer

Given,

pH of buffer = 5.32

pKa of acetic acid = 4.74

initial mmoles of acetic acid = 10 mmol

let x mmoles of acetate is added

then using Hendersen-Hasselbalck equation,

pH = pKa + log(acetate/acetic acid)

5.32 = 4.74 + log(x/(10-x))

38 - 3.8x = x

x = 38/4.8 = 7.92 mmol

so amount of acetate needed to prepare this buffer = 7.92 mmol

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.