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Question 17 Calculate the increase of entropy (in J/K) when 73 g of ice melts at

ID: 904799 • Letter: Q

Question

Question 17 Calculate the increase of entropy (in J/K) when 73 g of ice melts at 0 degree C and 1 atm. (The heat of fusion for ice is 6,000 J/mol.) Question 18 Calculate the change in entropy (in J/K) when 34.0 g of water is heated from 12.4 degree C to 70.5 degree C at 1 atm. (The specific heat is 4.184 J/(g-K).) Question 19 Calculate the change in entropy (in J/K) when 66.6 g of nitrogen gas is heated at a constant pressure of 1.50 atm from 22.8 degree C to 83.5 degree C. (The molar specific heats are Cv is 20.8 J/(mol-K) and Cp is 29.1 J/(mol-K) .)

Explanation / Answer

There are multiple questions here . i am allowed to answer only 1 at a time. I will answer 1st one for you. Please ask other as different question.

17.
latent heat of fusion of ice, L = 333.55 J/g

Q = m*L
    = 73g * 333.55 J/g
    =24349.15 J

T= 0 oC = 273 K

delta S = Q/T
      = 24349.15/ 273
      = 89.2 J/K

Answer: 89.2 J/K

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