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The following chemical equilibria are studied in this experiment. Indicate the d

ID: 902017 • Letter: T

Question

The following chemical equilibria are studied in this experiment.

Indicate the direction, left or right, of the equilibrium shift when the accompanying stress is applied to the system.

Choose the correct answer with explanation.

NH3(aq) is added to Ag+(aq) + Cl-(aq) D AgCl(s)

HNO3(aq) is added to Ag2CO3(s) D Ag+(aq) + CO32-(aq)

KI(aq) is added to Ag+(aq) + 2NH3(aq) D [Ag(NH3)2]+(aq)

Na2S(aq) is added to AgI(s) D Ag+(aq) + I-(aq)

KOH(aq) is added to CH3COOH(aq) + H2O(l) D H3O+(aq) + CH3CO2-(aq)

Shift to right. Removes Ag+, it will react with sulfide to produce Ag2S(s).

Shift to left. Removes Ag+, it will react with iodide to produce AgI(s).

Shift to right. Removes CO32-(aq), it will react with the acid to produce carbon dioxide plus water.

Shift to right. Removes acid, it will react with hydroxide to produce water.

Shift to left. Removes Ag+, it will react with ammonia to produce [Ag(NH3)2]+(aq)

-A.B.C.D.E.

NH3(aq) is added to Ag+(aq) + Cl-(aq) D AgCl(s)

-A.B.C.D.E.

HNO3(aq) is added to Ag2CO3(s) D Ag+(aq) + CO32-(aq)

-A.B.C.D.E.

KI(aq) is added to Ag+(aq) + 2NH3(aq) D [Ag(NH3)2]+(aq)

-A.B.C.D.E.

Na2S(aq) is added to AgI(s) D Ag+(aq) + I-(aq)

-A.B.C.D.E.

KOH(aq) is added to CH3COOH(aq) + H2O(l) D H3O+(aq) + CH3CO2-(aq)

A.

Shift to right. Removes Ag+, it will react with sulfide to produce Ag2S(s).

B.

Shift to left. Removes Ag+, it will react with iodide to produce AgI(s).

C.

Shift to right. Removes CO32-(aq), it will react with the acid to produce carbon dioxide plus water.

D.

Shift to right. Removes acid, it will react with hydroxide to produce water.

E.

Shift to left. Removes Ag+, it will react with ammonia to produce [Ag(NH3)2]+(aq)

Explanation / Answer

1. NH3(aq) is added to Ag+(aq) + Cl-(aq) --> AgCl(s)

Answer : Shift to left. Removes Ag+, it will react with ammonia to produce [Ag(NH3)2]+(aq)

2) HNO3(aq) is added to Ag2CO3(s) --> Ag+(aq) + CO32-(aq)

Answer : Shift to right. Removes CO32-(aq), it will react with the acid to produce carbon dioxide plus water.

CO3-2 + 2H+ --> H2O + CO2

3) KI(aq) is added to Ag+(aq) + 2NH3(aq) --> [Ag(NH3)2]+(aq)

Answer : Shift to left. Removes Ag+, it will react with iodide to produce AgI(s).

4) KOH(aq) is added to CH3COOH(aq) + H2O(l) --> H3O+(aq) + CH3CO2-(aq)

Answer : Shift to right. Removes acid, it will react with hydroxide to produce water.

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