rate of uncatalyzed reaction , please explian very well , and step by step, this

Question

rate of uncatalyzed reaction , please explian very well , and step by step, this is my 2nd time that I have posted this question , thanks

This section requires longer answers, be specific, provide details, and show your work. (10 points) The rate of an uncatalyzed reaction is 0.2M/sec. With an enzyme, the new rate is 15 Au M/sec. The concentration of the reactants was 1 did the enzyme decrease the energy of activation? (What is the difference in 12) 10mM for each experiment. How much the two energies of activation?) tiada

Explanation / Answer

K= K0E-Ea/RT

For reaction in the absence of catalyst

0.2= K0e-Ea/RT (1)

in the second case

15*10-6 = Ko e-Ea1/RT (2)

(1)/(2)= 0.2/15*10-6= e-(1/RT)*(Ea-Ea1)

13333.3 = e-1/RT( Ea-Ea1)

ln (13333.3) = -1/RT( Ea-Ea1)

9.498 = -1/RT ( Ea-Ea1)

9.498*8.314(joules/mole.K) 298.15 ( assumed since this is an enzyme reaction)= -(Ea-Ea1)

-23543.88 joules.mole= decrease in activation energy

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