rams ? Part A What is the molar mass of butane, CH10? Express your answer to fou

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rams ? Part A What is the molar mass of butane, CH10? Express your answer to four significant figures and include the appropriate units. View Available Hint(s) 58.12-5 mole Previous Answers Correct The molar mass of C,Ho is based on the number of each kind of atom in the formula, and values from the periodic table Simlarty,the mdlar ma 0 41120 /mole) + 10/01.00s g/mole) 58.12g/mole masses for H20 and CO2 are H0: 2(1.008 g/mole) + (16.00 g/mole) 18.02 g/mole Co2: (12.01 g/mole) +2(16.00 g/mole) 44.01 g/mole The molar mass can be used to convert between grams and moles of a compound. Solving stoichiometry problems that involve mass Now that you know the molar masses of the relevant compounds, you are ready to start solving stoichiometry problems In general, the typical strategy is 1. Convert from grams of compound X to moles of compound X using the molar mass of compound X Convert from moles of compound X to moles of compound Y using the coefficients in the balanced chemical equation 3 Convert from moles of compound Y to grams of compound Y using the molar mass of compound Y ? Part B Calculate the mass of water produced when 5.00 g of butane reacts with excess oxygen Express youranswer to three significant figures and include the appropriate units. View Available Hint(s) Value Units Submit

Explanation / Answer

Part B)

2C4H10 + 13O2 --> 8CO2 + 10H2O

moles butane = 5 g/58.12 g/mol = 0.086 moles

moles CO2 formed = 0.086 moles x 8 = 0.172 moles

mass CO2 produced = 0.172 moles x 44 g/mol = 7.57 g

Part C)

moles CO2 = 54.1 g/44 g/mol = 1.23 moles

moles C4H10 needed = 2 x 1.23/8 = 0.31 moles

mass C4H10 needed = 0.31 moles x 58.12 g/mol = 1.80 g

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