11. Hydrogen, bromine and HBr are in equilibrium in a 1-L container. H2(g) + Br2

Question

11. Hydrogen, bromine and HBr are in equilibrium in a 1-L container. H2(g) + Br2(g) 2 HBr(g) + 68 kJ How will each of the following changes affect the indicated quantities? Write increase, decrease or no change. Change Some H2 is added to the container The temperature of the gases in the container is increased Partial pressure of HBr is increased Volume of flask is increased a. (Bral 2. Kp for the following reaction is 0.16 at 25°C. The enthalpy change for the reaction at standared conditions is -344 kJ. 2 NOBr(g) 2 NO(g) + Br2(g) offact of the following changes on the equilibrium. Write which way the

Explanation / Answer

Condition 1:

According to Le Chatlier's Principle, if a stress is placed on an equilibrium, the equilibrium will shift in the direction which relieves the stress. When H2 is added to the container, the stress is excess of H2. So the equilibrium will shift to the products side.

Br2 Decreases

HBr Increases

Kc No change

Condition 2:

The effect of temperature on equilibrium will change only the equilibrium constant.

Br2 No change

HBr No change

Kc Increases

Condition 3:

According to Le Chatlier's Principle, if a stress is placed on an equilibrium, the equilibrium will shift in the direction which relieves the stress. When partial pressure of HBr is increased, the stress is excess of partial pressure in product side. So the equilibrium will shift to the products side to counteract the pressure.

Br2 Decreases

HBr Increases

Kc No change

Condition 4:

An increase in volume will have no effect on the equilibrium since you have equal moles of reactants and products.

Br2 No change

HBr No change

Kc No change

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