11. Fill in the following table with the expected numbers (E) of bees from the F
ID: 282317 • Letter: 1
Question
11. Fill in the following table with the expected numbers (E) of bees from the F2 generation for the phenotypes listed. Please note that the observed numbers (O) have been inputted for you already. (5 marks) (HINT: You will need to use your hypothesis to perform these calculations.) When inputting the numbers that you calculated for the expected (E), please round to the nearest whole number (e.g 52). Observed (O) Expected (E) 382 365 wings, lack stripes 122 wings, lack stripes wings, 124 122 black stripes with white rt wings black stripes with white otal number of bees in 650 650Explanation / Answer
Answer:
11)
Chi square value = 3.377
13 a) Degree of freedom = Number of categories - 1 = 4 - 1 = 3
13 b) The P-Value is 0.337. The result is not significant at p < 0.05
14 a) Since P-value (0.337) is greater than the significance level (0.05), therefore, the results are not statistically significant and the Null Hypothesis is not rejected. The difference between expected and observed frequency of progeny
15 a) The genes for wing length and stripe pattern are not linked.
15 b) The genes for wing length and stripe pattern are not linked because there is no statistically significant difference between the observed frequency and expected frequency.
Phenotype Observed Frequency (O) Expected Frequency (E (O-E) (O-E)^2/E Long wings, black stripes 382 365 17 0.792 Short wings, black stripes 111 122 -11 0.992 Long wings, black stripes with white spots 124 122 2 0.033 Short wings, black stripes with white spots 33 41 -8 1.561 Total Number of bees 650 650 Chi Square (sum) 3.377Related Questions
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