How do I find the half life if I was given that Solution A1 (0.008 M) took 261.6

Question

How do I find the half life if I was given that Solution A1 (0.008 M) took 261.6 seconds to change color and Solution B1 (0.04 M) took 388.8 seconds to change color and the average temperature was 55.5 C?

Then my experient data shows: Initial T / Final T / Initial time / Final time / Half-Life

So what would my half life calculations be using the data below?

Run 1 85C / 84.5 / 0 / 0:54:97 _____ (thats 0 minutes, 54 seconds, 97 milliseconds)

Run 2 75C / 72.0 / 0 / 1:32:78 _____

Run 3 65.2C / 63.5 / 0 / 3:12:22 _____

Run 4 45.2C / 47.0 / 0 / 29:55:97 _____

Run 5 55.0 C and my lab says that the half life for run 5 is the average of the two half lives (A1 and B1) so what would that be?

Using the data above what would be:

t1/2, k, ln k, 1/T

Run 1 357.9K _____ _____ _____ _____

Run 2 346.65K _____ _____ _____ _____

Run 3 337.4K _____ _____ _____ _____

Run 4 319.15K _____ _____ _____ _____

Run 5 328.15K _____ _____ _____ _____

And after I find that for all 5 runs, how do I find the EA?

#2 Whats the order of increasing ability to catalyze the decomposition of H2O2? ____ < _______ < _______ (KI, FeCl1, bovine catalase)

Note: please explain how you get the answers (briefly)

Explanation / Answer

Fecl > bovine catalase > KI

FeCl is an example of homogeneous and KI is heterogeneous and bovine catalase is an example of enzymatic catalysis

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