How do I do this? As for number 2, is it just using the A=-log(I/I0) and then wh

Question

How do I do this? As for number 2, is it just using the A=-log(I/I0) and then whatever that value is will come out to be the absorbance amount?

2) (a) When a UV spectrophotometer reports an absorbance of 1.0, what percent of the incident UV light is absorbed by the sample? (b) What percent of the incident light is absorbed when A = 2.0? (c) When A = 0.5?

2) (3 pts) (a) When a UV spectrophotometer reports an absorbance of 1.0, what percent of the incident UV light is absorbed by the sample? (b) What percent of the incident light is absorbed when A = 207 (c) When A-0.5?

Explanation / Answer

A = - log T = -log It/ Io

% of absorbance = incident light - transmitted light = It - Io

a) Given that absorbance A= 1

A = -log It/ Io

1 = -log It/ Io

It/ Io = 10-1 = 0.1

It = 0.1 Io = 10 % of Io

So, transmitted light = 10%

incident light = 100 %

Therefore, absorbed light = 100 % - 10 % = 90 %

b) Given that absorbance A= 2

A = -log It/ Io

2 = -log It/ Io

It/ Io = 10-2 = 0.01

It = 0.1 Io = 1 % of Io

So, transmitted light = 1%

incident light = 100 %

Therefore,

absorbed light = 100 % - 1 % = 99 %

c) Given that absorbance A= 0.5

A = -log It/ Io

0.5 = -log It/ Io

It/ Io = 10-0.5 = 0.32

It = 0.32 Io = 32 % of Io

So, transmitted light = 32 %

incident light = 100 %

Therefore,

absorbed light = 100 % - 32 % = 68 %

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