1. Find H ° for the reaction C3H8( g ) + 5 O2( g ) 3 CO2( g ) + 4 H2O( l ). H °

Question

1. Find H° for the reaction C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(l).

H° = -2046 kJ for the reaction: C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g), and the heat of vaporization of water is 44.0 kJ/mol. Note that H2O is a liquid in the first reaction and a gas in the second.

2.Determine the sign of S° for each of the following:

I. The mixing of two gases at a given temperature and pressure
II. C(s) + 2 H2O(g) CO2(g) + 2 H2(g)

3. The following drawing is a representation of a reaction for which H° = -22 kJ. This reaction is likely to be

Explanation / Answer

Question 1

C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) H° = -2046 kJ ------(1)

H2O(l)-----> H2O(g) H° = 44 KJ/mol -------------(2)

We need the delta H for the reaction

C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(l).

Therefore using equation 1

= delta H = delta H of (1) + (- 4* delta H of 2 )

= -2046 -4*44 = -2222 KJ

Question 2

S° is negative for I and positive for II

Question 3

nonspontaneous at low temperatures and spontaneous at high temperatures

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