How would you solve for this equation ina bit more detail i am stuck at the mani
ID: 889321 • Letter: H
Question
How would you solve for this equation ina bit more detail i am stuck at the manipulation for the equations to get the final answer of delta h to -97.7 5.2 fhel 1.) The combination of coal and steam produces a mixture called syngas, which can be used as a feel of as a starting material for other reactions. If we assume coal can be represented by graphite, the equation for the production of syngas is: 1.) The combination of coal and steam produces a mixture called syngas, which can 2C (s) + 2H20 (g)- CH4 (g) + CO2 (g) Determine Honn for this reaction, given the following reacti ons: C (s) + H2O (g) CO (g) + H2 (g CO (g) + H2O (g) CO2(g) + H2 (g) CH4 (g) + H2O (g) 3 H2 (g) + CO (g)·rR AH -41.2 kJ Ho-206.1 kl bAlso calculate the amount of heat released/absorbed when 25.0 grams of coal (carbon) reacts with excess steam.Explanation / Answer
a)
The trick here is to write the main reaction in terms of 3 reactions mentioned below.
Let these 3reactions be numbered 1,2 and 3 respectively from top to bottom.
Main reaction =2*reaction 1 + 1* reaction 2 - 1*reaction 3
so,
delta Ho rxn = 2*delta Ho (reaction 1) + 1*delta Ho (reaction 2) - 1*delta Ho (reaction 3)
= 2*131.3 + 1*(-41.2) - 1*(206.1)
= 15.3 KJ
b)
As calculated above,
when 2 mol of of C reacts to release 15.3 KJ
25 g = 25/12 = 2.083mol.
so2.083 mol of C will react to give, 15.3*2.083/2 = 15.9 KJ
Answer: 15.9 KJ
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