adenine, a component of nucleic acids, has the mass percent composition: 44.45%

Question

adenine, a component of nucleic acids, has the mass percent composition: 44.45% C , 3.73% H , 51.82% N . Its molecular mass is 135.14 u . What is the molecular formula ? adenine, a component of nucleic acids, has the mass percent composition: 44.45% C , 3.73% H , 51.82% N . Its molecular mass is 135.14 u . What is the molecular formula ? adenine, a component of nucleic acids, has the mass percent composition: 44.45% C , 3.73% H , 51.82% N . Its molecular mass is 135.14 u . What is the molecular formula ?

Explanation / Answer

Solution :-

44.45% C , 3.73% H , 51.82% N . Its molecular mass is 135.14 u . What is the molecular formula ?

Lets assume we have 100 g sample then

Mass of C= 44.45 g

Mass of H = 3.73 g

Mass of N= 51.82 g

Now lets calculate moles of each element

Moles of C 44.45g /12.01 g per mol = 3.70 mol C

Moles of H = 3.73 g / 1.0079 g per mol = 3.70 mol H

Moles of N = 51.82 g / 14.007 g per mol = 3.07 mol N

Moles of the all elements are same therefore the ratio of each element is 1:1:1

Therefore empirical formula = CHN

Now lets find the empirical formula mass

CHN = 12.01 * 1.0079 + 14.007 = =27.0249 g

Now lets find the ratio of the molar mass to empirical formula mass

N= molar mass / empirical formula mass

N= 135.14 g /27.0249 g = 5

Therefore

Molecular formula = N*empirical formula

                                  = 5 * CHN

                                 = C5H5N5

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