I am doing a cyclic Voltammetry lab in one of my chemistry classes this week and

Q: I am doing a cyclic Voltammetry lab in one of my chemistry classes this week and

2 mM = 0.002 M solution Molarity = (mass/molar mass) X 1000/v in ml 0.002 M = (mass/ 108) X (1000/25) mass = (0.002 X 108) / 40 = 0.0054 gm of Quinone is required. we have to take 0.0054 gm of quinone and have dissolve and make the solution volume to 25 ml.

ID: 887220 • Letter: I

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I am doing a cyclic Voltammetry lab in one of my chemistry classes this week and I'm completely stumped as to how to make the solutions:

Prepare 25 mL of a 2 mM solution of quinone with 0.1 M TBAHFP as the supporting electrolyte in acetonitrile using a 25 mL volumetric flask.

It also says that I will need to add successive amounts of dry ethanol to the solution to make 0.05 M, 0.1 M, 0.2 M, 0.5 M and 1 M in ethanol. The molecular weight of ethanol is 46.0634 g mol^-1 and the density is 0.789 g mL^-1.

Any help would be greatly appreciated. Please show all work so I can understand this stuff. Thanks!

Explanation / Answer

2 mM = 0.002 M solution

Molarity = (mass/molar mass) X 1000/v in ml

0.002 M = (mass/ 108) X (1000/25)

mass = (0.002 X 108) / 40

= 0.0054 gm of Quinone is required.

we have to take 0.0054 gm of quinone and have dissolve and make the solution volume to 25 ml.

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I am doing a cyclic Voltammetry lab in one of my chemistry classes this week and

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I am doing a cyclic Voltammetry lab in one of my chemistry classes this week and

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