A sample co siting of perfect gas Click Submit to complete this assessment. Ques

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A sample co siting of perfect gas

Click Submit to complete this assessment. Question 5 A sample consisting of 2.00 moles of perfect gas molecules, for which Cv.m22.5R, initially at 111 kPa and 277 K, is heated reversibly to 356 K at constant volume. (a) For this problem, the final pressure is (b) For this problem, the change in intemal energy is [ Joules. kPa (b) For this problem, the change in internal energy is (c) For this problem, the heat is (d) For this problem, the work is For each part, please record answer to nearest whole number without decimal places. Joules Joules Click Submit to complete this assessment search the web and Windows

Explanation / Answer

A) P1/T1 = P2/T2

111/277 = P2/356

P2 = 142.65 kPa

b) delta U = n * Cv * (T2-T1)

                 = 2*2.5*8.314*(356-277)

                 = 3284.03J

C) THE AMOUNT OF HEAT EXCHANGES AT CONSTANT VOLUME(qv ) = change in internal energy = 3284.03J

D) AT CONSTANT VOLUME MEANS V2-V1 =0

   W = P ext(V2-V1) = 0 J

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