Shown below is the equilibrium phase diagram of copper-silver system, include al

Question

Shown below is the equilibrium phase diagram of copper-silver system, include all workings.

(a) For a 20 wt% Cu – 80 wt% Ag alloy at 900°C, (a) identify the phase(s) present; (b)

determine the composition(s) of the phases(s); and (c) calculate the relative amount of

each phase present.

(b) For an 80 wt% Cu – 20 wt% Ag alloy at 900°C, (a) identify the phase(s) present; (b)

determine the composition(s) of the phases(s); and (c) calculate the relative amount of

each phase present.

(c) For an 80 wt% Cu – 20 wt% Ag alloy at 778°C, (a) identify the phase(s) present; (b)

determine the composition(s) of the phases(s); and (c) calculate the relative amount of

Explanation / Answer

(a) For a 20wt% Cu-80wt%Ag alloy at 900 oC

(a) We have liquid phase only

(b) Composition of phase would be 100% liquid of 20wt%Cu-80wt%Ag

(c) Relative composition of liquid phase would be 1

(b) For 80wt%Cu-20wt%Ag alloy at 900 oC

(a) Phases present would be alpha(solid)+Liquid

(b) Composition of phases solid = 9wt%Ag-91wt%Cu and liquid composition would be 43wt%Ag-57wt%Cu

(c) relative amount of each phase

solid = 43-20/43-9 = 0.676

liquid = 20-9/43-9 = 0.324

(c) For 80wt%Cu-20wt%Ag alloy at 778 oC

(a) Phases present would be solid phase only

(b) Composition of solid phase would be 100% of 80wt%Cu-20wt%Ag

(c) Relative composition of solid phase would be 1

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