Shown below is a model of SF_6 having an orientation in which one or more atoms

Question

Shown below is a model of SF_6 having an orientation in which one or more atoms are hidden from view. What is the indicated bond angle? A) 90 degree B) less than 109.5 degree but greater than 90 degree C) less than 120 degree but greater than 109.5 degree D) 120 degree Consider Li^+, F^-, and O^2-. Which ratio should be the largest? A) (radius Li+)/(radius F^-) B) (radius F^-)/(radius Li^+) C) (radius O^2-)/(radius Li^+) D) (radius Li^+)/(radius O^2-) What is the average speed (actually the root-mean-square speed) of a carbon monoxide molecule at 27 degree C? A) 450 m/s B) 517 m/s C) 412 m/s D) 514 m/s A balloon contains 0.76 mol N_2, 0.18 mol Ar, 0.031 mol He, and 0.026 mol H_2 at739 mm Hg. what is the partial pressure of Ar? A) 23 mm Hg B) 19 mm H C) 130 mm Hg D) 560 mm Hg Which of the following ionic compounds would be expected to have the highest lattice energy? A) KI B) KBr C) KCl D) KF Which compound is most likely to exist as a gas or liquid at room temperature? A) CaI_2 B) CCl_4 C) Al_4C_3 D) WC What is the general trend in ionization energy and electron affinity values? A) Both increase as one traverses a period from left to right and both increase as one descends a group. B) Both increase as one traverses a period from left to right and both decrease as one descends a group. C) Both decrease as one traverses a period from left to right and both decrease as one descends a group D) Both decrease as one traverses a period from left to right and both increase as one descends a group.

Explanation / Answer

Q1.

angle must be 90°

since this is a square plane, therefore 360° is the overal measure of the plane

4 quadrants --> 360/4 = 90 °

Q2.

Identify larges radius --< O2-

identify shortest radius --> Li+

so

C is the largest ratio

Q3.

RMS = sqrt(3*R*T/MW)

MW = 28 g/mol = 28*10^-3 kg/mol

so

RMS = sqrt((3*8.314*300)/( 28*10^-3 ))

RMS = 516.948 m/s

Q4.

x-Ar = mol of Ar / (total mol)

x-Ar = 0.18 / (0.76+0.18+0.031+0.026) = 0.18054

P-Ar = X-aR*PT = 0.18054*739 = 133 mm Hg

best answer is C

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