10. Consider the following reaction: CS 2 (g) + 4 H 2 (g) <====> CH 4 (g) + 2 H

Question

10. Consider the following reaction:

CS2 (g) + 4 H2 (g) <====> CH4 (g) + 2 H2S (g)

Calculate the value of Keq if the equilibrium concentrations are [CS2] = 0.180, [H2] = 0.250, [CH4] = 0.0100, and [H2S] = 0.0200.

Express your answer using only a number or numbers without text. Report your result in scientific notation and to the proper number of significant figures. Use the following format to express a number in scientific notation: 1.23E4 (or 1.23E-4 if the exponent is negative). Note that there are no spaces within the expression. All numbers are measured.

Explanation / Answer

For the reaction,

Keq = [CH4][H2S]^2/[CS2][H2]^4

Given,

[CH4] = 0.01 M

[H2S] = 0.02 M

[CS2] = 0.180 M

[H2] = 0.250

Feed the values,

Keq = (0.01 x 0.02^2)/(0.18 x 0.25^4)

       = 4 x 10^-6/7.03 x 10^-4

       = 5.69 x 10^-3

thus, Keq for the reaction is 0.00569 or 5.69 x 10^-3

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