Look at Point l of this reaction. titration of diprotic oxalic acid pH 7.0 E F B

Question

Look at Point l of this reaction. titration of diprotic oxalic acid pH 7.0 E F B C 100 mL 200 mL. vol of NaOH oxalate anion, (ox) s in solution. It is a weak base. Two of the reactions can occur at this point (Reaction 3 (Cx) T aa) H2O(l) H (Ox) (aa) OH (aa) Kb 1.6 x10 (Reaction 4) HCCX) (aa) H2O(l) a H2(Ox)(aa) OH (aa) Kb 1.7x10 Assume that Reaction 3 is the dominant equilibrium to consider when determining the solution's pH. What is the pH of the solution if we start with 150 mL of 0.11 M H2(ox) and titrate it with 0.11 M NaoH? Use the plot for the amounts of NaOH added during the reaction. a. 8.4 Choose one answer. b. 5.6 c. 7.0 d. 8.6

Explanation / Answer

The correct answer is C pH = 7 because here the volume of NaOH solution is 150 ml so the moles of both acid and base becomes equal . solution becomes neutral.

Moles of acid : 0.11 M *150 mL = 0.0165

Moles of base : 0.11 M *150 mL = 0.0165

Means [H+] =[OH-]

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