Question 10 Elemental S reacts with O2 to form SO3 according to the reaction 2S

Question

Question 10 Elemental S reacts with O2 to form SO3 according to the reaction 2S + 3O2 - > 2SO3 as depicted here. Part A How many O2 molecules are needed to react with 6.07 g of S? Express your answer numerically in units of molecules. Part B What is the theoretical yield of SO3 produced by the quantities described in Part A? Express your answer numerically in grams. Next, consider a situation in which all of the S is consumed before all of the O2 reacts, or one in which you have excess S because all of the O2 has been used up.

Explanation / Answer

Part A:

mol S= mass/MW= 6.07g/32.066g/mol= 0.189 mol

2 mol S -------- 3 mol O2

0.189 mol S ------- x= 0.2835 mol O2

1 mol of O2 molecules ---------- 6.02 x 1023 molecules

0.2835 mol O2 ------------- x= 1.71 x1023 molecules of O2

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Part B:

2 mol of S -------------- 2 mol SO3

0.189 mol S ---------------x= 0.189 mol SO3

mass SO3= 0.189 mol x 80.0642g/mol= 15.13g (theoretical yield)

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