H2 reacts with the halogens (X2) according to the following reaction: H2( g )+X2

Question

H2 reacts with the halogens (X2) according to the following reaction:
H2(g)+X2(g)2HX(g)
where X2 can be Cl2, Br2, or I2.

206.6

A. Calculate H for the reaction between hydrogen and Cl2 at 276 K

B. Calculate S for the reaction between hydrogen and Cl2.

C. Calculate G for the reaction between hydrogen and Cl2.

D. Calculate Kp for the reaction between hydrogen and Cl2.

Reactant/Product Hf(kJ/mol) Sf(J/molK) H2(g) 0 130.7 Cl2(g) 0 223.1 HCl(g) -92.3 186.9 Br2(g) 30.9 245.5 HBr(g) -36.3 198.7 I2(g) 62.42 260.69 HI(g) 26.5

206.6

Explanation / Answer

A)   H2 + Cl2 -------------------> 2 HCl

?Horxn = ?Hoproducts - ?Horeactants

            = 2 ?HoHCl - (?HoH2 + ?HoCl2)

            = 2 x -92.3 - (0+0)

             = -184.6 kJ /mol

?Horxn   = -184.6 kJ /mol ---------------------------(answer)

B) H2 + Cl2 ---------------------> 2 HCl

?Sorxn = ?Soproducts - ?Soreactants

            = 2 ?SoHCl - (?SoH2 + ?SoCl2)

            = 2 x 186.9 - (130.7+223.1)

             = 20 J /mol K

?Sorxn= 20 J /mol K ---------------------------(answer)

C)

?Go = ?Ho - T ?So

         = -184.6 - 276 x 20 x 10^-3

          = -190.12 kJ/mol

?Go = -190.12 kJ/mol ---------------------------(answer)

D)

?Go = - RT ln Kp

-190.12 = - 8.314 x 10^-3 x 276 x ln Kp

ln Kp = 82.85

Kp = e ^82.85

Kp = 9.58 x 10^35 ---------------------------(answer)

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