Which of the following will increase the cell potential for the following reacti
ID: 881800 • Letter: W
Question
Which of the following will increase the cell potential for the following reaction:
2Fe3+(aq) + 3Zn(s) 3Zn2+(aq) + 2Fe(s)
Add solid iron to the system
Increase concentration of Fe3+ in the solution
Add zinc solid
Increase the concentration of zinc ion in solution
Dilute the entire system
Remove water from the entire system
Add solid iron to the system
Increase concentration of Fe3+ in the solution
Add zinc solid
Increase the concentration of zinc ion in solution
Dilute the entire system
Remove water from the entire system
Explanation / Answer
We must apply Le Chatelier concepts
First, let us state the Le Chatelier principle which deals with changes in an equilibrium:
The statement is as follows:
If any equilibrium is disturbed, that is, change in conditions such as P,T, concentration, partial pressure, etc.., the system will counterbalance such change in order to favour the system's equilbirium.
The reaction:
2Fe3+(aq) + 3Zn(s) 3Zn2+(aq) + 2Fe(s)
Add solid iron to the system --> Solid Iron is not really in the equilbirium expression, so there will not be an increase in equilbirium
Increase concentration of Fe3+ in the solution --> True, if we want to increase products, we need to increase reactants in order to favour even more production of products
Add zinc solid Increase the concentration of zinc ion in solution --> solids will not increase Q ratio in the equilbirium, since the activity of solids= 1
Dilute the entire system --> The product/reactant ratio is given as
Q = [Zn+2]^3 / [Fe+3]^2
note that dilution will affect much greater in Zn+2, So Q will decrease
which favours Nernst equation Ecell = E° - (RT/nF) x lnQ
So expect more product formation
Remove water from the entire system --> Removing water will increase concentration, as stated before, this will not favour product formation
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