Del Mar College. CHEMx(de www.saplinglearning.com ×eChegg.com Q Create a New Stu

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Del Mar College. CHEMx(de www.saplinglearning.com ×eChegg.com Q Create a New Study Set l x P Pandora Internet Radic c Dwww.saplinglearning.com/ibiscms/mod/ibis/view.php?id=1834506 7/31/2015 11:55 PM 38.5/100 Assignment Information Available From 7/27/2015 10:00 AM Due Date: Points Possible Grade Category: Graded Description: Policies: Gradebook #Attempts Score Print Calculator Periadic Table 95 Question 7 of 15 7/31/2015 11:55 PM 98 Map 100 sapling learning 95 What are the concentrations of OH and H* in a 0.00061 M solution of Ba(OH)2 at 25 °C? Assume complete dissociation Homework 95 You can check your answers. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up. You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer 10 Help With This Topic Web Help &Videos; Technical Support and Bug Reports 12 13 Previous Give Up & View Solution O Check Answer Next Exit 15 Hint Copyright © 2011-2015 Sapling Learning, Inc.-190 about us careers partners privacy policy terms of use contact ushelp 7/28/2015

Explanation / Answer

Answer –

We are given, [Ba(OH)2] = 0.00061 M and there is complete dissociation.

So, Ba(OH)2 -----> Ba2+ + 2OH-

So there are 2 moles of OH- in one Ba(OH)2, means the concentration also double

So, [OH-] = 2 * [Ba(OH)2]

                 = 2 * 0.00061 M

                 = 0.00122 M

Now we know the water ionization

Kw = [H+] [OH-]

We know, Kw = 1*10-14

So, 1*10-14= [H+] [OH-]

So, [H+] = 1*10-14 / [OH-]

              = 1*10-14 / 0.00122 M

              = 8.2*10-12 M

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