Balloons may contain tiny microscopic holes, which allow the gas particles withi
ID: 879679 • Letter: B
Question
Explanation / Answer
Looking at the data, it seems that it's missing information about the temperature, however we can calculate that through the ideal gas pressure:
PV = nRT ----->T = PV / nR
Let's calculate the Temperature of both gases:
T1 = 1.42 x 4.23 / (1.207/4) x 0.082 = 242.75 K
T2 = 1.42 x 4.23 / (6.085/20.18) x 0.082 = 242.93 K
v1 = (3RT/PM)1/2 = (3x0.082x242.75/4)1/2 = 3.86
v2 = (3x0.082x242.93/20.18)1/2 = 1.72
According to this result, the He balloon efuses faster than the Ne Balloon.
Now according to this and the rate:
rate1/rate2 = (M1/M2)1/2
rate1/rate2 = (4/20.18)1/2 = 0.4452
rate1 = 0.4452rate2
rate 2 = 1/0.4452 rate1 = 2.2461 rate1
This means that the He gas effuses 2.2461 times faster than Ne gas.
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